c – 如何初始化一个可变长度的unsigned char数组？

我读完了这篇文章( How to initialize a unsigned char array?),但它并没有完全回答我的问题.

我知道我可以像这样创建一个字符串数组：

const char *str[] =
{
  "first",
  "second",
  "third",
  "fourth"
};

如果我想写()这些我可以使用：write(fd,str [3],sizeof(str [3]));

但是,如果我需要一个可变长度的无符号字符数组呢？我试过这个：

const unsigned char *cmd[] =
{
  {0xfe, 0x58},
  {0xfe, 0x51},
  {0xfe, 0x7c, 0x01, 0x02, 0x00, 0x23},
  {0xfe, 0x3d, 0x02, 0x0f}
};

我得到gcc编译警告,如
*“标量初始化器周围的括号”
*“初始化使得指针来自整数而无需强制转换

最佳答案

这是一种方式

const unsigned char cmd1[] = {0xfe, 0x58};
const unsigned char cmd2[] = {0xfe, 0x51};
const unsigned char cmd3[] = {0xfe, 0x7c, 0x01, 0x02, 0x00, 0x23};
const unsigned char cmd4[] = {0xfe, 0x3d, 0x02, 0x0f};

const unsigned char *cmd[] =
{
  cmd1,
  cmd2,
  cmd3,
  cmd4
};

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